India’s premier educational institution, the Indian Institutes of Technology has removed the veil of secrecy and has revealed the IIT JEE 2012 cut-off marks to be eligible for admission in the just concluded IIT’s Joint Entrance Examination, called IIT JEE 2012.

For the first time in IIT JEE five decade history, the institute revealed minimum qualifying marks in each subject and also in aggregate form for different category of students.

A general category student will have to get 10 % in each subject, other backward class students (OBCs) nine percent and Scheduled Caste (SC), Scheduled Tribe (ST) and Physically Disabled (PD) students five percent.

In addition to these minimum marks, a student will have to clear aggregate cut to be eligible to be part of all India ranking. The aggregate cut-off for general category students is 35 %, for OBCs 31.5 % and SC/ST/PD 17.5 %.    

It will mean that if a general category student scores 14 marks out of 136 in all three subjects — Physics, Chemistry and Mathematics — has overall aggregate cut-off of 143 out of total 408 marks, he or she will be eligible for the rank.

According to IIT professors, providing the qualifying marks will help the students to evaluate the performance as soon as they leave the IIT-JEE examination center and will reduce stress on students. It will also help the students in preparing for IIT-JEE examination, said another IIT professor.

Source: HT